Will it fly?

[Maengelito]

derek, look at it this way. you have a car attached to a strain gauge. when you start the treadmill, there will initially be some strain shown merely because of the friction between the tires and the treadmill and wheel bearings, etc. for this exercise though we are negating the force of friction though. if you pull on the strain gauge which is attached the car, it will show basically no change (aside from that countered by friction, which we negated) but the car will still move as you pull it forward. its vector will be whatever value you pull it (lets say a 1m long treadmill) but the tires will have rotated that distance and thensome because of the opposite direction of the treadmill. the amount of force exerted is still the same to cover that 1m distance. the change in the value of the vector is caused by you pulling on the strain gauge (ie: the jet thrusters or propellers or whatever kind of plane we're talking about) and is not dependent at all on the freely moving wheels of the car (or landing gear of the plane)

i tried to lay it out as basically as i could, but i'm not sure if its a better explanation as i've seen others write